6x^2+11x+2=4

Solution for 6x^2+11x+2=4 equation:

6x^2+11x+2=4

We move all terms to the left:

6x^2+11x+2-(4)=0

We add all the numbers together, and all the variables

6x^2+11x-2=0

a = 6; b = 11; c = -2;
Δ = b2-4ac
Δ = 112-4·6·(-2)
Δ = 169
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{169}=13$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(11)-13}{2*6}=\frac{-24}{12}
=-2
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(11)+13}{2*6}=\frac{2}{12}
=1/6
$